Tags: ajax,xmlhttprequest

Sort by: Date / Title /

  1. 5 months ago by fandelost
    1. function ajax(url, vars, callbackFunction) { var request = new XMLHttpRequest(); request.open("POST", url, true); request.setRequestHeader("Content-Type", "application/x-www-form-urlencoded"); request.onreadystatechange = function() { if (request.readyState == 4 && request.status == 200) { if (request.responseText) { callbackFunction(request.responseText); } } }; request.send(vars); }

First / Previous / Next / Last / Page 1 of 1 (1 posteets)